(2x+8)=(3x^2)

Solution for (2x+8)=(3x^2) equation:

(2x+8)=(3x^2)

We move all terms to the left:

(2x+8)-((3x^2))=0

determiningTheFunctionDomain
(2x+8)-3x^2=0

We add all the numbers together, and all the variables

-3x^2+(2x+8)=0

We get rid of parentheses

-3x^2+2x+8=0

a = -3; b = 2; c = +8;
Δ = b2-4ac
Δ = 22-4·(-3)·8
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-10}{2*-3}=\frac{-12}{-6}
=+2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+10}{2*-3}=\frac{8}{-6}
=-1+1/3
$